Probability PYQs for UPSC (2011-2024) | Solved Questions & PDF Download
Why Probability Matters in UPSC CSAT?
Year-Wise Probability PYQs (2011-2024)
(a) 0.40
(b) 0.20
(c) 0.16
(d) 0.04
Solution:
Given that,
A around archery target of diameter 1 m is marked with four scoring regions from the centre outwards as red, blue, yellow and white.
The radius of the red band is 0.20 m.
The width of all the remaining bands is equal.
Now,
The area of red band = π(0.20)2 = 0.04 π
Radius of round archery target = 1/2 = 0.5m
Total area = π(0.5)2= 0.25 π
Probability = 0.04 π/0.25 π = 0.16
Hence option (c) is correct
Q2. A bag contains 15 red balls and 20 black balls. Each ball is numbered either 1 or 2 or 3. 20% of the red balls are numbered 1 and 40% of them are numbered 3. Similarly, among the black balls, 45% are numbered 2 and 30% are numbered 3. A boy picks a ball at random. He wins if the ball is red and numbered 3 or if it is black and numbered 1 or 2. What are the chances of his winning? [CSAT 2018]
(a) 1/2
(b) 4/7
(c) 5/9
(d) 12/13
Solution:
Given that,
A bag contains 15 red balls and 20 black balls.
Each ball is numbered either 1 or 2 or 3.
20% of the red balls are numbered 1 and 40% of them are numbered 3.
Similarly, among the black balls, 45% are numbered 2 and 30% are numbered 3.
A boy picks a ball at random.
He wins if the ball is red and numbered 3 or if it is black and numbered 1 or 2.
Now,
Total number of balls = 20 + 15 = 35
Red balls numbered 3 = (40/100) x 15 = 6
Red balls numbered 1 = 20% of 15 = 3
Black balls numbered 2 = 45% of 20 = 9
Black balls numbered 3 = 30% of 20 = 6
Black balls numbered 1 = 20 - (9 + 6) = 5
Black balls numbered 1 or 2 = 9 + 5 = 14
Probability of winning = (6 + 14)/35 = 4/7
Hence option (b) is correct
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