Trains Problems PYQs for UPSC (2011-2024) | Solved Questions & PDF Download

Master Train Problems for UPSC with solved Previous Year Questions (PYQs) from 2011 to 2024. This comprehensive guide provides step-by-step solutions, shortcut formulas, and a free downloadable PDF to help you solve all types of train-related problems in UPSC CSAT.

Why Trains Problems Matters in UPSC CSAT?

Train problems are frequently asked in UPSC CSAT (Paper II) to test:

· Your ability to calculate speed, distance, and time

· Understanding of relative speed concepts

· Skills in solving real-world scenario-based problems

This page covers all train-related PYQs with smart calculation techniques.

Year-Wise Trains Problems PYQs (2011-2024)

Q1. A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/h more than its original speed. If it takes 3 hours to complete the total journey, what is the original speed of the train in km/h? [CSAT 2013]

(a) 24

(b) 33

(d) 66

Solution:

Given that,

A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/h more than its original speed.

It takes 3 hours to complete the total journey.

Now,

Let the original speed of train = S km/hr

So,

63/S + 72/(S + 6) = 3......(i)

Solving the equation

(S - 42) (3S + 9) = 0

When

S - 42 = 0 , S = 42 Km/hr

3S + 9 = 0 , S = - 3 (which is not possible)

Thus, S = 42 Km/hr

Hence option (c) is correct

Q2. A freight train left Delhi for Mumbai at an average speed of 40 km/h. Two hours later, an express train left Delhi for Mumbai, following the freight train on a parallel track at an average speed of 60 km/h. How far from Delhi would the express train meet the freight train? [CSAT 2017]

(a) 480 km

(b) 260 km

(d) 120 km

Solution:

Given that,

A freight train left Delhi for Mumbai at an average speed of 40 km/h.

Two hours later, an express train left Delhi for Mumbai, following the freight train on a parallel track at an average speed of 60 km/h.

Now,

In 2 hr freight train will cover the distance = 40 x 2 = 80 km

Relative speed of trains = 60 - 40 = 20 km/hr

Time both train meets = 80/20 = 4 hrs

Distance = speed x time

= 60 x 4 = 240 km

Hence option (c) is correct

Q3. A train 200 meters long is moving at the rate of 40 km/h. In how many seconds will it cross a man standing near the railway line? [CSAT 2018]

(a) 12

(b) 15

(d) 18

Solution:

Given that,

A train 200 meters long is moving at the rate of 40 km/h.

Now,

Time to cross the man = M

Time = 200/(40 x 5/18) = (200 x 9)/100 = 18 seconds

Hence option (d) is correct

ANSWER KEY

1. C

2. C

3. D

Download Train Problems PYQs PDF

➡️ Download the complete set of Number Series PYQs (2011-2024) with solutions in PDF format.
➡️ Click Here to Download PDF

FAQs on Train Problems for UPSC

1. How many train problems appear in CSAT?

➡️ Typically 1-2 questions annually in CSAT Paper II.

2. What are the most common train problems?

· Calculating speed of train

· Crossing stationary/moving objects

· Overtaking problems

· Platform/bridge crossing problems

3. Any quick calculation tips?

✔️ Always convert km/h to m/s (×5/18)

✔️ For same direction: subtract speeds
✔️ For opposite direction: add speeds
✔️ Remember train length must be added when crossing platforms

Conclusion

Mastering Train Problems PYQs can secure you easy marks in CSAT. This page provides:

✅ All PYQs from 2011-2024
✅ PDF with 40+ solved problems
✅ Time-saving calculation methods

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· Quantitative Aptitude PYQs